Request for you

[mario]

(09-21-2009 01:15 AM)ido Wrote:  [quote='mario' pid='2297' dateline='1253431371']

Quote:Any pair has a 71% chance to give us a good number in 4 sessions!
Then exist some strategy, we don't need to play any pair! So the chances increase!

Hi,Mario,
Don't you understand whay I wrote that having a pairs for strictly 4 drawselections is a miracle?

A 71% chance of having a good number in 4 sessions is not much sufficient!
Because even a 95% chance of having a good number in 4 sessions is not sufficient!

Do you immagine if you realy want 1000 pounds in 2 days risking 3350 pounds but having only 71% chance of having a win?In case of negative result it's logical to suppose you'l would retent again -now,how ready you'l be to risk 3350 pounds for second time if you know to have 71% of chance ???

I thing that it's justifyed to invest a time &to do efforts only if such an research activity seriosly increases the probability of win ,the margin 95%-98%(as the 100% of chance simply dasn't exist!)is the very profitable one second me,wathever strategy or shoice the player would have to do or intraprend.

We have obtain 99% if we wait 16 consecutive draws, but the sum for risk is very big even so the result is almost sure.

71% is a good chance, I obtained a sufficient chain of wins to put a wonderful summ in my pocket.
But, indeed this 71% chance must increase with a strategy.

If I understand you use that balls with the same colour and if its have 10-12 overdue you can play 8 consecutive draws because 20 overdue is very rare.

If I substract the both numbers for a pair obtain value=7.
Only a simulation in history of 49s prove that this strategy works and I think to make it.


Have you a such simulation that prove the results?